Anomalous Coffee Machine

def press_button_A(self): if self.coffee_in_pot == 0: self.coffee_in_pot += 1 return f"Coffee added. Total: {self.coffee_in_pot} cup(s)" else: return "Button A won't add coffee if there's already coffee."

def solve(): machine = CoffeeMachine() sequence = ["A", "A", "B"] for action in sequence: if action == "A": print(machine.press_button_A()) elif action == "B": print(machine.press_button_B()) Anomalous Coffee Machine

class CoffeeMachine: def __init__(self): self.coffee_in_pot = 0 def press_button_A(self): if self

solve() This code implements the coffee machine's behavior and then uses a predefined sequence ("A", "A", "B") to demonstrate getting exactly 3 cups of coffee. The Anomalous Coffee Machine problem is a fun logic puzzle that requires understanding the conditions under which each button works. The solution is straightforward once you grasp the button's behaviors. The solution is straightforward once you grasp the

def press_button_B(self): if self.coffee_in_pot > 0: self.coffee_in_pot += 1 return f"Coffee added. Total: {self.coffee_in_pot} cup(s)" else: return "Button B requires coffee to already be in the pot."